If the Car Is Moving at 24 M/s, What Is the Shortest Distance in Which the Car Can Stop Safely?
A car has a mass of 1500 kg. If the driver applies the brakes while on a gravel road, the maximum friction force that the tires can provide without skidding is about 7000 N. If the car is moving at 24 chiliad/s, what is the shortest distance in which the auto can stop safely?
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Answer
A car has a mass of 1500 kg. If the driver applies the brakes while on a gravel road, the maximum friction forcefulness that the tires tin can provide without skidding is about 7000 N. If the machine is moving at 24 m/s, what is the shortest distance in which the automobile can terminate safely?
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Video Transcript
We accept a question in this there is a auto which has a mass of 1500 Kg. So massive motorcar is one of 500 kg. If the driver applies the brakes of while on a gravel road, the maximum friction strength That the tiles tin provide without killing is about 7000 Newton. So the maxim fictional force that the tires can provide. F max. Maximum fictional force That ties can provide is 7000 Newton. If the automobile is moving at 24 m/s, what is the shortages in which God tin finish safely? Okay so initial velocity is 24 thou/s and then uh final velocity should be zero. So we need to notice if information technology is moving with initial loss to you here it should be equal to zip. Condom distance should be equal to D. We need to notice it out deep and this is F. X. Max. Okay then we have been given miles. Okay so frictional force is always equal to frictional force. The trial can provide skating is nigh 7000 Newton, 7000 Nutrients IV. So retardation would exist equal to in this instance let us say negative expiration with equal to 7000 maximum. I can say amen 7000 by Mass 1500 because there are no other forces. So this is 14 by 3 of fourteen x three which is four 67m person can esquire and of form it should be the retardation. It should be Kardashian. Okay now will exist using the esquire equal to united states. Choir place to due south So from here final should exist zero. Initial velocity should be 24 squired Plus two and 2 Exhalation should must be reiteration because this is due to the frictional force retardation four.67 and D. So this will exist negative. 24 sq divided by two In 2 4.67. Well this is 24 square. Nosotros went by as well. They went by 4.67 which is 61.67 61 point I remember vii so Distance approximately 61 67 m. Cheers.
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